Questions on Algebra: Evaluation of expressions, parentheses answered by real tutors!

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Tutors Answer Your Questions about expressions (FREE)


Question 751351: I don't know how to solve (5/3)+(3/2x)=(1/6).
Answer by stanbon(57307) About Me  (Show Source):
You can put this solution on YOUR website!
solve (5/3)+(3/2)x = (1/6)
-------
Multiply thru by 6 to get:
2*5 + 3*3x = 1
------------
9x = -9
x = -1
============
Cheers,
Stan H.
-----


Question 751043: Please help me solve this equation
Evaluate each expression:
(5/3)^0
32^2/5
Simplify each expression:
(3y^2)(4y^5)
(5a^4a^2)^3
Simplyify the expression and eliminate any negative exponent:
(4x^2y^4)(2x^5y^-2)
(2u^3v^2)(3uy^-3)^2

Found 2 solutions by lwsshak3, dkppathak:
Answer by lwsshak3(6491) About Me  (Show Source):
You can put this solution on YOUR website!
Evaluate each expression:
(5/3)^0=1(any expression raised to zero power=1
32^2/5=fifth root of 32=2 squared=4
Simplify each expression:
(3y^2)(4y^5)=12y^7
(5a^4a^2)^3=5^3a^12a^2=125a^12a^2
Simplyify the expression and eliminate any negative exponent:
(4x^2y^4)(2x^5y^-2)=8x^7y^2
(2u^3v^2)(3uy^-3)^2=(2u^3v^2)(9u^2y^-6)=18u^5v^2/y^6

Answer by dkppathak(29) About Me  (Show Source):
You can put this solution on YOUR website!
(5/3)^0=0 as zero power on any number is 0
32^2/5 =(2^5) ^2/5= 2^2=4
Simplify each expression:
(3y^2)(4y^5)=12 y^2+5 =12y^7
(5a^4a^2)^3=5a^4+2 =5a^6
Simplyify the expression and eliminate any negative exponent:
(4x^2y^4)(2x^5y^-2)=8x^2+5 y4-2 =8x^7 y2
(2u^3v^2)(3uy^-3)^2 = (6u^3v^2)(9u^2y^-6) =54u^5v^2y^-6


Question 750911: Wendy bought 7 bags. Each bag costs the same amount. She paid the cashier $90 and received g dollars as change. What was the cost of each bag in terms of g?
Found 2 solutions by JoeTaxpayer, jim_thompson5910:
Answer by JoeTaxpayer(112) About Me  (Show Source):
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7 bags cost (90-g)
1 bag cost (90-g)/7

Answer by jim_thompson5910(28579) About Me  (Show Source):
You can put this solution on YOUR website!
let b = cost of each bag

Since she bought 7 bags, this means the total cost of them is 7b dollars.

Since she received g dollars in change after paying $90, this implies that 7b < 90 and

g = 90 - 7b

since that's how you compute change (change = amount paid - cost)

Now solve for b

g+=+90+-+7b

g+-+90++=+-7b

-7b+=+g+-+90

b+=+%28g+-+90%29%2F%28-7%29

b+=+%2890+-+g%29%2F7

So the cost of each bag, in terms of g, is b+=+%2890+-+g%29%2F7


Question 750332: what is the answer of (6^1/4)^2/3 could you explain to me please ? and (8/125)^-4/3, thank you

Answer by ankor@dixie-net.com(15649) About Me  (Show Source):
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what is the answer of
(6^1/4)^2/3 = 6^(2/12) (multiply the exponents here
6^(1/6) (reduce the fraction)
:
(8/125)^-4/3,
inverting the fraction gets rid of the negative
(125/8)^(4/3)
find the cube root
(5/2)^4
Find the 4th power
625/16


Question 750478: 4/3-6=-8
Answer by jim_thompson5910(28579) About Me  (Show Source):
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4/3-6=-8

4/(-3)=-8

-1.333=-8 ... FALSE

-------------------------------------------------------

4/3-6=-8

1.333-6=-8

-4.667=-8 ... FALSE

-------------------------------------------------------

So 4/3-6=-8 is never true

My guess is that a variable is missing.


Question 750428: 6xy from -12xy
Answer by tommyt3rd(514) About Me  (Show Source):
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if you mean subtract then

-12xy-6xy=-18xy


:)


Question 750053: factorise completely: 27xy + 9x
Answer by Cromlix(307) About Me  (Show Source):
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27 xy + 9x
9x(3y + 1)


Question 750052: A butcher buys xkg of beef daily,he takes 2% of the beefhome and sells the rest.Find x if the butcher takes home 15kg of beef in 6 days.
Answer by josgarithmetic(1507) About Me  (Show Source):
You can put this solution on YOUR website!
Six days... Bought 6x kg of beef. 2% of 6x kg was taken home. That was 15 kg.

0.02%2A6x=15
x=15%2F%286%2A2%2A0.01%29
x=15%2F%2812%2A0.01%29=5%2F%284%2A0.01%29=%285%2F4%29%2A100=highlight%28125%29 kg.


Question 750050: Alli was born in 1983.How old is he now? Give the answer in Roman numerals.
Answer by Edwin McCravy(8908) About Me  (Show Source):
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 2013
-1983
-----
   30 years old.

30 is three 10s, and X is 10 in Roman numerals. 
So three tens in Roman numerals is three X's or XXX.

Edwin


Question 734148: (3-4i)(1+4i)

Answer by tommyt3rd(514) About Me  (Show Source):
You can put this solution on YOUR website!
Using distribution we can write
%0D%0A%283-4i%29%281%2B4i%29%0D%0A

3%281%2B4i%29-4i%281%2B4i%29%0D%0A

3%2B12i-4i%2B16


19%2B8i



:)



Question 741011: (5n-2)3n-(5n-2)(n-1) Is equivalent to ?
Answer by tommyt3rd(514) About Me  (Show Source):
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Using grouping w can write:

(5n-2)3n-(5n-2)(n-1)=(5n-2)(3n-(n-1))=(5n-2)(2n+1)


Question 741012: Simplify 5(x-2)+2(3x^2-12x+12
Answer by tommyt3rd(514) About Me  (Show Source):
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Use distribution then combine like terms:

5%28x-2%29%2B2%283x%5E2-12x%2B12%29=5x-10%2B6x%5E2%2B24x%2B24=6x%5E2-19x%2B14

:)


Question 744206: How do you solve (x-4)(x+8)=0
Answer by tommyt3rd(514) About Me  (Show Source):
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We can use the zero product property:

(x-4)(x+8)=0 means
x-4=0 or x+8=0

so that x=4 or x=-8



:)


Question 741131: find all pair of integers factors with number 23
Answer by tommyt3rd(514) About Me  (Show Source):
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please repost - this question is not clear :)


Question 748921: solve 4-(-6)6
Answer by tommyt3rd(514) About Me  (Show Source):
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Evaluation....
4-(-6)6=4-((-6)(6))=4-(-36)=4+36=40

:)


Question 749591: Multiply (-5/6)(1/8)(-3/7)(-1/7)
Answer by Alan3354(30993) About Me  (Show Source):
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Multiply (-5/6)(1/8)(-3/7)(-1/7)
--------
Multiply the NUMs
5*1*3*1 = 15
---
Multiply the DENs
6*8*7*7 = 2352
--> 15/2352 = 5/784
----
There are 3 minus signs, and odd number --> negative
====================
= -5/784


Question 749518: which of the following statements is equivalent to the expression -2s-5(6t-7s)
Answer by rfer(12657) About Me  (Show Source):
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-2s-30t+35s=
33s-30t


Question 749527: A woman's age added thrice her daughter's age amounts to 80years. Five years ago,she was nine times as old as her daughter. How old is each now?
Answer by lwsshak3(6491) About Me  (Show Source):
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A woman's age added thrice her daughter's age amounts to 80years. Five years ago,she was nine times as old as her daughter. How old is each now?
***
Now:
let x=daughter's age
let y=woman's age
y+3x=80
..
5 yrs ago:
x-5=daughter's age
y-5=woman's age
woman nine times as old as her daughter
y-5=9(x-5)
..
y+3x=80
y-5=9(x-5)=9x-45
..
y+3x=80
y-9x=-40
subtract
12x=120
x=10
y=80-3x=50
daughter's age=10
woman's age=50


Question 748847: Insert Parentheses to make the following statement true:
7+3*5-6-2*4=6
Thank you

Answer by MathTherapy(1423) About Me  (Show Source):
You can put this solution on YOUR website!
Insert Parentheses to make the following statement true:
7+3*5-6-2*4=6
Thank you

highlight_green%287+%2B+3+%2A+5+-+%286+-+2%29+%2A+4+=+6%29


======
Check
======
7+%2B+3+%2A+5+-+%286+-+2%29+%2A+4+=+6

7+%2B+15+-+4+%2A+4+=+6

7+%2B+15+-+16+=+6

22+-+16+=+6


Question 748750: (6^-7)^3
Answer by stanbon(57307) About Me  (Show Source):
You can put this solution on YOUR website!
(6^-7)^3
------
= 6^(-21)
----
= 1/[6^21]
===============
Cheers,
Stan H.
=====================


Question 748509: 3a+b+5a+2b
Answer by lenny460(764) About Me  (Show Source):
You can put this solution on YOUR website!
3a + b + 5a + 2b
Combine like terms:
3a + 5a = 8a
b + 2b = 3b


Answer:
8a + 3b






Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: obuong3@aol.com


Question 746234: solve the inequality
-5/7> 1/4- v/2

Answer by kekegeter (57) About Me  (Show Source):
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-5/7>1/4-v/2
-5/7>-2v+1/2^2
-20>-7*2v+7
v>27/14
v Є [27/14,∞]


Question 747007: how to solve the square root of x over 5 plus 4 equals 14
Answer by Cromlix(307) About Me  (Show Source):
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square root of x over 5 plus 4 equals 14
square root of x/5 = 14 - 4
square root of x/5 = 10
square root of x = 50
x = 50^2
x = 2500


Question 747633: -7/12+3/4-(-5/8)-13/24
Answer by checkley79(3050) About Me  (Show Source):
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-7/12+3/4-(-5/8)-13/24
-7/12+3/4+5/8-13/24 FIND THE LOWEST COMMON DENOMINATOR.
12=1*2*2*3
4=1*2*2
8=1*2*2*2
24=1*2*2*2*3
LCD=1*2*2*2*3=24
(-7*2+3*6+5*3-13*1)/24
(-14+18+15-13)/24
6/24=1/4 ANS.


Question 747410: 3{[6(x-4)+5]-2[5(x+8)-3]} The directions says to simplify the problem. I have tried everything but nothing I do allows me to come up with the right.
Answer by stanbon(57307) About Me  (Show Source):
You can put this solution on YOUR website!
3{[6(x-4)+5]-2[5(x+8)-3]}
-------------
= 3{[6x-24+5]-2[5x+40-3]}
-------------
= 3{6x-19-10x+74}
-----
= 3{-4x+55}
-----
= -12x+165
======================
Cheers,
Stan H.
======================


Question 747378: what is the excluded value of -s over 3s +4
Answer by Alan3354(30993) About Me  (Show Source):
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what is the excluded value of -s over 3s +4
----------
It's the value of s that makes the denominator = 0.


Question 747366: what is the excluded value p when -3 over 2p to the second power - p
Answer by stanbon(57307) About Me  (Show Source):
You can put this solution on YOUR website!
what is the excluded value p when -3 over 2p to the second power - p
------
-3/(2p^2-p)
-----
The denominator cannot be zero.
----
Solve:
2p^2-p = 0
p(2p-1) = 0
---
p = 0 or 2p-1 = 0
---
p = 0 or 2p = 1
----
p = 0 or p = 1/2
--------------------
p = 0 or p = 1/2
Those are the excluded values.
Cheers,
Stan H.
==============


Question 747262: 4xsquared + 9x + 7 = 0
Answer by jim_thompson5910(28579) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula to solve for x

x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

x+=+%28-%289%29%2B-sqrt%28%289%29%5E2-4%284%29%287%29%29%29%2F%282%284%29%29 Plug in a+=+4, b+=+9, c+=+7

x+=+%28-9%2B-sqrt%2881-%28112%29%29%29%2F%288%29

x+=+%28-9%2B-sqrt%28-31%29%29%2F8

x+=+%28-9%2Bsqrt%28-31%29%29%2F8 or x+=+%28-9-sqrt%28-31%29%29%2F8

x+=+%28-9%2Bi%2Asqrt%2831%29%29%2F8 or x+=+%28-9-i%2Asqrt%2831%29%29%2F8

So the two solutions are x+=+%28-9%2Bi%2Asqrt%2831%29%29%2F8 or x+=+%28-9-i%2Asqrt%2831%29%29%2F8


Question 742672: reduce the expression(factor separately the numerator and the denominator, and then simplify; 5-x/x-5
Answer by tommyt3rd(514) About Me  (Show Source):
You can put this solution on YOUR website!
If you mean to write:
5-x/x-5
then its
5-1-5=-1 as long as x is not 0
But if you mean:

%0D%0A%285-x%29%2F%28x-5%29%0D%0A%0D%0A
then we notice that 5-x and x-5 are opposite in value. therefore their quotient is -1:


(as long as x does not equal -5)



Also notice that is just a coincidence that both expressions have the same value
:)



Question 738846: 30-5 (3+1)
Answer by tommyt3rd(514) About Me  (Show Source):
You can put this solution on YOUR website!
by following the order of operations we write:
30-5 (3+1)=30-5(4)=30-20=10


Question 743061: Divide: 6+i
-----
5-i
Write the expression in standard form.

Answer by tommyt3rd(514) About Me  (Show Source):

Question 746493: evaluate 5a when a = 4

Answer by Cromlix(307) About Me  (Show Source):
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When a = 4
5a = 5 x 4 = 20


Question 745884: I know the answer to the problem but not sure how they got it. 30-5(4-2)
Answer by nerdybill(6958) About Me  (Show Source):
You can put this solution on YOUR website!
Apply the "order of operations" (PEMDAS)
30-5(4-2)
parentheses first:
30-5(2)
multiplication next:
30-10
finally, subtraction
20


Question 745814: Evaluate ((7pi)/6) to the nearest hundredth. The angle is given in radians.
Answer by stanbon(57307) About Me  (Show Source):
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Evaluate ((7pi)/6) to the nearest hundredth. The angle is given in radians.
---------
Assuming you are convert to degrees:
= [(7/6)pi]
=====
= (7/6)*180
-----
= 7*30
-----
= 210 degrees
======================
Cheers,
Stan H.


Question 745720: The problem says: "A car is traveling at the speed of 55 mph.You want to write an algebraic expression to show how far the car will travel in a certain number of hours. What will the constant? The Variable?" i know the constant is a number that stays the same and doesnt change, so im assuming that it would be the speed, right?
I think that the variable would be the number of hours. But im not sure if i need to multiply or divide. Would it be 55x? x= the time traveled... Am I correct?

Answer by ankor@dixie-net.com(15649) About Me  (Show Source):
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"A car is traveling at the speed of 55 mph.You want to write an algebraic expression to show how far the car will travel in a certain number of hours. What will the constant? The Variable?"
:
I think you're right
:
The equation will be
d(x) = 55x
where
d(x) = the distance as a function of time
x = the variable, time in hours
55 = the slope
there is no constant


Question 745320: what is (x+7)-(x-5)?

Answer by tommyt3rd(514) About Me  (Show Source):
You can put this solution on YOUR website!
(x+7)-(x-5)=x+7-x-(-5)=7+5=12


Question 745198: I am trying to help my son with some algebra. I am wanting to confirm the following problems. Can someone answer the following and please show your work if possible??? I have 3 different problems below as I read somewhere you were limited to 3 questions. I wasn't sure if I could send one question w/3 different math problems or do I need to send 3 different questions. If one at a time please answer any below and I will send two more questions. If you can answer all 3 BLESS YOU! Also note problem #3, I did not know how to say 4square on here you know like 4(With the little 2 up high beside it meaning 4x4 =16
#1) 17 + 3(8-5)???
Is this the way to solve it:
8-5 = 3 & 17+3 = 20 So the last step would be 20 - 3 = 17 OR 20x3 =60???


#2) 5*6-3*8???
Is this the way to solve it:
5*6=30 & 3*8=24 So the last step would be 30 - 24 = 6


#1) 28+ 4(Square) /2???
Is this the way to solve it:
4square (Same as 4x4) = 16 THEN 16/2 = 8 So the last step would be 28+8=36

Answer by ankor@dixie-net.com(15649) About Me  (Show Source):
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#1) 17 + 3(8-5)???
First do the math inside the bracket
17 + 3(3) =
multiply by what's inside the bracket by 3
17 + 9 = 26
:
#2) 5*6-3*8???
Using the order of operations; Exponent, mult, divide, add, subtract
Unless brackets are used, then do the math inside the bracket first
Is this the way to solve it: So you are right on this one
5*6=30 & 3*8=24 So the last step would be 30 - 24 = 6

#1) Assuming the problem is: 28%2B+4%5E2%2F2=
You solved it correctly


Question 745162: Simplify (1-(3/x^3))/(4+(1/X^2))
Answer by stanbon(57307) About Me  (Show Source):
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Simplify (1-(3/x^3))/(4+(1/X^2))
-----
[(x^2-3)/x^3] / [(4x^2 +1)/x^2]
------
Invert the denominator and multiply:
-------
[(x^2-3)/x^3] * [x^2/(4x^2 +1)]
------------
= [(x^2-3)/x]
------
= [(x^2-3)/x(4x^2+1)]
=======================
Cheers,
Stan H.
========================


Question 744747: Evaluate
37
∑ (2K-10)
K=7

Answer by tommyt3rd(514) About Me  (Show Source):
You can put this solution on YOUR website!
sum%28%282k-10%29%2C+k=7%2C+37%29
2%2Asum%28k%2C+k=7%2C+37%29-10%2Asum%281%2C+k=7%2C+37%29
The sums are a little tricky because we are not summing from 1 to a number...
%28%2837%29%2837%2B1%29%2B%287-1%29%287%2B1-1%29%29-%2810%2837-7%2B1%29%29
1364-310%29

or 1054


Question 744663: s(r-4) r=4 s=6
Answer by erika514(38) About Me  (Show Source):
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Hi,
For this problem we are going to plug in our values for r and s into the given expression. In this problem r=4 and s=6, so when we insert them in for their variables we get 6(4-4). When we simplify, we subtract what is inside the parentheses first (4-4) to get 0 and the we multiply the 6 in front of the parentheses to get 6*0=0 Our final answer to our problem is 0. Hope this helps you and let me know if you have any more questions.


Question 744202: How do you factor 4x³+108
Answer by lenny460(764) About Me  (Show Source):
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How do you factor 4x^3 + 108
Factor:
4(x^3 + 27)
We can now factor (x^3 + 27) using the sum of cubes formula:
a^3 + b^3 = (a + b)(a^2 - ab + b^2)

Answer:
4(x + 3)(x^2 - 3x + 9)











Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: obuong3@aol.com


Question 743957: How to evaluate the expression, if possible (-32^1/5)
Answer by Alan3354(30993) About Me  (Show Source):
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How to evaluate the expression, if possible (-32^1/5)
--------------
There are 5 5th roots of -32
The principal root is -2.


Question 741508: Do you now two numbers that are multipled to get -96, and added to get -46?
Answer by ankor@dixie-net.com(15649) About Me  (Show Source):
You can put this solution on YOUR website!
two numbers that are multiplied to get -96, and added to get -46?
Two numbers x & y, two equations
xy = -96
x+y= -46
y = (-46-x)
replace y in the 1st equation
x(-46-x) = -96
-46x - x^2 = -96
x^2 + 46x = 96; multiplied by -1
A quadratic equation
x^2 + 46x - 96 = 0
Factors to
(x+48)(x-2) = 0
two solutions
x = -48 then y = 2
and
x = +2 then y = -48


Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320