SOLUTION: ``solve each system of equations by the substitution method
6x-3y=5
X+2y=0
Algebra.Com
Question 999611: ``solve each system of equations by the substitution method
6x-3y=5
X+2y=0
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Solve the second one and substitute into the first equation...
6x-3y=5
x+2y=0
and
x = -2y
and
6(-2y)-3y=5
-12y-3y=5
-15y=5
divide by -15 and get
y = -1/3
x = 2(-1/3) = 2/3
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