SOLUTION: a coffee shop decides to blend a coffee that sells for$12 per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 per pound. how much of each
Algebra.Com
Question 99931: a coffee shop decides to blend a coffee that sells for$12 per pound with a coffee that sells for $9 per pound to produce a blend that will sell for $10 per pound. how much of each should be used to yield 20 pounds of the new blend?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
12x+9(20-x)=10*20
12x+180-9x=200
3x=200-180
3x=20
x=20/3 pounds of $12 coffee is needed.
20-6 2/3=13 1/3 or 40/3 pounds of $9 coffee is needed.
proof
12*20/3+9*40/3=200
240/3+360/3=200
80+120=200
200=200
RELATED QUESTIONS
a coffee shop decides to blend a coffee that sells for 12$ per pound with a coffee that... (answered by lwsshak3)
A coffee shop decides to blend a coffee that sells for $12 per pound with a coffee that... (answered by Mathtut,nerdybill)
The Golden Cup Coffee Shop sells Hawaiian Kona coffee for $36.50 per pound
and Sulawesi... (answered by stanbon)
The Golden Cup Coffee Shop sells Hawain Kona coffee for $36.50 per pound and Sulawesi... (answered by jorel1380,adamhen894)
A coffee shop blends a coffee that sells for $12 per pound with a coffee that sells for... (answered by lwsshak3)
A coffee manufacturer wants to market a new blend 100 pounds of coffee that sells for... (answered by Edwin McCravy)
The coffee counter charges $10 per pound for Kenyan French roast coffee and $9 per pound... (answered by josgarithmetic,ikleyn)
a coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of... (answered by josmiceli)
a merchant wants to produce 80 pounds of coffee by blending coffee that sells for $3 per... (answered by richwmiller)