SOLUTION: Hi, Math problems I have no idea how to figure out and understand.I am not sure they are equation category. Please help x-4/11=3/5 Divide & simplify-32/45+48/35 Simlify-6

Question 997146: Hi,
Math problems I have no idea how to figure out and understand.I am not sure they are equation category. Please help
x-4/11=3/5
Divide & simplify-32/45+48/35
Simlify-6x*2-2y*2-5(3y*2+2x*2)
3(2x-1)=27-2
Clear fraction--3/2x1=2/5x4
Thank you so much, Betty
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x-(4/11)=(3/5)
multiply everything by 55
55x-20=33
55x=53
x=(53/55)
============
3(2x-1)=25
6x-3=25
6x=28
x=(14/3)
=========
(3/2x)=(2/5x^4)
cross multiply
15x^4=4x
x^3=(4/15)
x=(4/15)^(1/3)
=========
-32/45+48/35 ;;This has a common denominator of 1575. Multiply -32 by (35) {-1120} and 48 by 45 {2160}. The answer is 1040/1575, and that reduces to 208/315.
Simlify-6x^2-2y^2-5(3y^2+2x^2) I am editing out the asterisks to put in exponents. This may or may not be what was intended.
-6x^2-2y^2-15y^2-10x^2=
-16x^2-17y^2
RELATED QUESTIONS
Hi. I need some help with a math problem. log[x] (x+4) + log[3] (x-2) = 3 I have no... (answered by richard1234)

my math teacher is literally horrible at teaching and every year 75% of his class fails... (answered by rodriguezh2)

I have x+3y-3=0. I figured out how to turn it into the correct equation of y=-1/3x+1. We... (answered by MathTherapy)

Hi i'm not sure this is the exact correct category for my specific word problem but this... (answered by Alan3354)

Hi, I'm in a hybrid math class at my college, so i don't get to see my teacher for... (answered by ewatrrr,Edwin McCravy)

Hi can you please help me figure this problem. I am solving for x and y. the equation is... (answered by Alan3354,bucky)

Id have a question; I should find out what the possible rational roots of x^3 - 4x^2... (answered by Alan3354)

Determine which two equations represent parallel lines. (a) y = 9x � 7 (b) y = �9x + 7... (answered by checkley75)

I am working on my math packet for school. I came across a section in it, in which i... (answered by Theo)