SOLUTION: show that the quadratic equation x^2+2px＋p(p－1)＝0 has two unequal real roots for any positive values of p.

Question 993998: show that the quadratic equation x^2+2px＋p(p－1)＝0 has two unequal real roots for any positive values of p.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

and p is given to be a real number . This means the square root expression does not disappear, and the plus&minus nature of the two roots insures that x is two unequal values.

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SOLUTION: show that the quadratic equation x^2+2px&#65291;p(p&#65293;1)&#65309;0 has two unequal real roots for any positive values of p.

SOLUTION: show that the quadratic equation x^2+2px＋p(p－1)＝0 has two unequal real roots for any positive values of p.