SOLUTION: Use the definition of limit to verify that:
(1). lim x->3 (5-2x) = - 1
2). lim x->0 (4x+7) = 7
(3). lim x->7 (2x)/(x^2+1) = 1
Please explain how you solved.
Thank
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Question 988780: Use the definition of limit to verify that:
(1). lim x->3 (5-2x) = - 1
2). lim x->0 (4x+7) = 7
(3). lim x->7 (2x)/(x^2+1) = 1
Please explain how you solved.
Thank you
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ L\ \Leftrightarrow\ \forall\,\epsilon\,\in\,\mathbb{R}\,>\,0\,\exists\,\delta\,\in\,\mathbb{R}\,>\,0\,:\,0\,<\,|x\ -\ a|\,<\,\delta\,\Rightarrow\,|f(x)\ -\ L|\,<\,\epsilon)
|\,<\,\epsilon)
Choose 
. Then 
whenever |\ <\ \epsilon)
John
My calculator said it, I believe it, that settles it
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