SOLUTION: Please tell me if I did the following problem correctly: If y varies inversely as x and y=3, when x=6. Find y when x=36. This is what I came up with: 3/36=y/6 36*y=36y 3

Question 98655: Please tell me if I did the following problem correctly:
If y varies inversely as x and y=3, when x=6. Find y when x=36.
This is what I came up with:
3/36=y/6
36*y=36y
3*6=18
18/36=1/2
So when x=36, y=1/2.
Thank you for your input.

Answer by malakumar_kos@yahoo.com(315) (Show Source): You can put this solution on YOUR website!

If y varies inversely as x and y=3, when x=6. Find y when x=36.
y varies inversely as x or y = k/x
k = xy where k is a proportionality
constant
when x= 6 y =3 k = 6.3 = 18

when x = 36 y = k/36 = 18/36 = 1/2
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