SOLUTION: The length of a rectangular backyard is 8 meters longer than the width. If the are is equal to 92 square meters, what are the dimensions of the backyard? Round to the nearest thous

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Question 986128: The length of a rectangular backyard is 8 meters longer than the width. If the are is equal to 92 square meters, what are the dimensions of the backyard? Round to the nearest thousandth. [only an algebraic solution will be accepted.]
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
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L=length; W=width=L-8m; A=area=92m^2
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=432 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 14.3923048454133, -6.39230484541326. Here's your graph:

.
L=14.392m ANSWER 1: The length is 14.392 meters.
W=L-8=14.392-8=6.392m ANSWER 2: The width is 6.392 meters.
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