SOLUTION: 1. Solve the system of equations by elimination. 2x2 + 6y2 = 168 2x2 + y2 = 43 Options: (�3, �5) (�5, �3) (�3, �3) (�5, �5) 2. A box contains 4 white ribbons a

Question 984964: 1. Solve the system of equations by elimination.
2x2 + 6y2 = 168
2x2 + y2 = 43
Options:
(�3, �5)
(�5, �3)
(�3, �3)
(�5, �5)
2. A box contains 4 white ribbons and 8 pink ribbons. Determine whether the events of picking a white ribbon and then another white ribbon without replacement are independent or dependent. Then identify the indicated probability.
Options:
independent; 1/11
dependent; 1/12
dependent; 1/11
independent; 1/12
3. Each of 5 boys randomly chooses a watch from 12 different styles. What is the probability that at least 2 boys choose the same type of watch?
Options:
≈ 0.7387
≈ 0.6181
≈ 0.5387
≈ 0.3819

4. Use the standard deviation to identify any outliers in the given data set.
{3, 6, 30, 9, 10, 8, 5, 4}

Options:
3
8
30
none

5. Bill wants to plant roses in his triangular plot. There will be 1 plant at a corner. Each row will have 6 additional plants. He wants the plot to have as many rows as possible with 150 rose plants. How many rows will Bill's plot have?
Options:
5 rows
6 rows
7 rows
8 rows

Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!

It is good that you placed only 5 problems in one request and not the entire textbook :)
In any case, I will solve here for you only one problem, namely, the first one.

1. Solve the system of equations by elimination

.

Distract the second equation from the first one (this is the elimination step). You will have

= = .

Hence, = = .
Therefore, = +/-5.

Now substitute the found value of y into the first system's equation. You will get

+ = ,

+ = ,

= - = .

= = .

x = +/-3.

Answer. x = +/-3, y = +/-5.

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