SOLUTION: The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x? Is this right? X^2=4y^2 X=2y+1 (2y+1)^2=(2y)^2 2y+1=2y Why can

Question 983928: The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x?
Is this right?
X^2=4y^2
X=2y+1
(2y+1)^2=(2y)^2
2y+1=2y
Why can't I take a square root of both side at this point?
The correct answer is 1/2.
Help would be greatly appreciated! Thanks a lot!
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!

The next steps will not involve square roots.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.

.

Since 1 does not equal 0:

.

Remember to consider both positive and negative cases when taking square roots.

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