SOLUTION: does t^2 = m^4pi^2R * (R^2/GmM) become t^2 = (m^4pi^2R^3/GmM) into t^2 = (m^3pi^2R^3/GM) so that t = square root of (m^3pi^2R/GM) ?

Question 983412: does
t^2 = m^4pi^2R * (R^2/GmM)
become
t^2 = (m^4pi^2R^3/GmM)
into
t^2 = (m^3pi^2R^3/GM)
so that
t = square root of (m^3pi^2R/GM)
?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Almost. Watch the cancellations and square root extractions carefully.

Unsure if you needed to take more care about parentheses for grouping to express what you have.
Exactly what is your starting equation? That's what is not clear.
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