SOLUTION: Hello every one, my question is:
d2y/dx2 - 24 cos (2t) = 4x
at t=0, x=3 and dy/dx = 4.
Solve it by using Laplace.
Any help please!
Algebra.Com
Question 983303: Hello every one, my question is:
d2y/dx2 - 24 cos (2t) = 4x
at t=0, x=3 and dy/dx = 4.
Solve it by using Laplace.
Any help please!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Your question is not properly configured.
Typically Laplace problems are in the time domain so your functions are functions of time, , .
You have a mixed t and x variable equation.
Also, for second derivative problems you need and .
Please correct and repost.
RELATED QUESTIONS
what is the product of order and degree of differential equation (d2y/ dx2) siny +... (answered by Bogz)
what is the product of order and degree of differential equation (d2y/dx2) siny +... (answered by Bogz)
From the following table of values x and y obtain
dy/dx and
d2y/dx2
at x = 1.2 .
x :... (answered by Fombitz)
every time i try this problem: {{{dy/dx}}} {{{ 4/cos(x)}}} my answer is... (answered by kensson)
every time i try this problem: {{{dy/dx}}} {{{ 4/cos(x)}}} my answer is... (answered by jsmallt9)
find dy/dx
x=9/t
y=t-t^2
I got as far as: dx/dt=-9t^-2 and dy/dt=1-2t... (answered by josgarithmetic)
Hello,
looking for a bit of guidance with Laplace transforms. Could I please be shown... (answered by rothauserc)
find dy/dx
x=t^2
y=square root of t^3
dx/dt= 2t
dy/dt=square root of 3t^2... (answered by josgarithmetic)