SOLUTION: Solve on the interval [0, 2pi] 2cos*2x=1

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Question 971541: Solve on the interval [0, 2pi]
2cos*2x=1

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
we'll do this in degrees and then translate to radians.

it's easier to show.

cos(2x) = .5

find cos^-1(.5) and you get 2x = 60 degrees.

that means that x is equal to 30 degrees.

the period of x is equal to 180 degrees because the frequency of x is equal to 2.

within that period of 180 degrees, you have 4 quadrants.

cosine is positive in the first and fourth quadrant.

30 degrees is in the first quadrant.

180 - 30 = 150 degrees is in the fourth quadrant.

within a 360 degree interval, you will get two full cycles of cosine(2x).

the cosine will be .5 at 30, 150, 30 + 180, 150 + 180.

that equates to 30, 150, 210, 330 degrees.

i'll show you the graph in degrees and then translate to radians.

$$$

here's the same graph in radians.
look under the graph for further comments.

$$$

instead of an interval from 0 to 360, you have an interval from 0 to 2pi.

conversion factor from degress to radians is radians = degrees * pi / 180.

30 degrees would be equal to 30/180 * pi which is equal to pi/6.

150 degrees would be equal to 150/180 * pi which is equal to 5pi/6.

210 degrees would be equal to 210/180 * pi which is equal to 7pi/6.

330 degrees would be equal to 330/180 * pi which is equal to 11pi/6.






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