SOLUTION: Find two consecutive odd integers such that 3 times the first integer is 5 more than twice the second. Please help me figure this one out. I also would like to no if there is a

Question 97151: Find two consecutive odd integers such that 3 times the first integer
is 5 more than twice the second. Please help me figure this one out.
I also would like to no if there is a way that I can check to see if the question I am about to ask is not already been answered somewhere? Can I search the web site some how? Could you tell me how if it is possible?
Thank you
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
1) Let x be the first odd integer, then x+2 will be the next consecutive odd integer.
From the problem description, you can write:
3x = 2(x+2)+5 Apply the distributive property to the right side.
3x = 2x+4+5 Simplify.
3x = 2x+9 Subtract 2x from both sides.
x = 9
The two integers are 9 and 11
Check:
3(9) = 2(11)+5
27 = 22+5
27 = 27
2) I don't know of an easy way to see if a similar problem to one you want help with has already been answered. You could try clicking on "Recent problems solved by all" and do a manual search but that could be quite time-consuming.
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