SOLUTION: solve for x. 2^(x^2-x+10)=16^(7-x) if there is more than one solution, separate them with commas.

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Question 964018: solve for x.
2^(x^2-x+10)=16^(7-x)
if there is more than one solution, separate them with commas.
Found 2 solutions by Murthy, MathTherapy:
Answer by Murthy(22)   (Show Source): You can put this solution on YOUR website!
2^(x^2-x+10)=16^(7-x)
Taking log with base 2 on both sides
(x^2-x+10)x log2(2)= (7-x)x log2(2^4)
=(x^2-x+10)x log(2)=(7-x)x 4xlog2(2)
cancel log2(2)on both sides
(x^2-x+10)=4(7-x)
x^2+3x-18=0
(x+6)(x-3)=0
therefore,
x=-6,3
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

solve for x.
2^(x^2-x+10)=16^(7-x)
if there is more than one solution, separate them with commas.






 --------- Bases are equal and so are their exponents 







(x + 6)(x - 3) = 0

    	OR	 

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