SOLUTION: what is the equation of the line that passes through (–2, 4) and is perpendicular to 6x + 3y = 2 A.) 1/3x + 1/2y = 2 B.) x - 2y = -10 C.) 2x - y = 10 D.) 2x + 3y =6

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Question 963925: what is the equation of the line that passes through (–2, 4) and is perpendicular to 6x + 3y = 2
A.) 1/3x + 1/2y = 2
B.) x - 2y = -10
C.) 2x - y = 10
D.) 2x + 3y =6
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The slope for line perpendicular to will be because in general, slope of will be so perpendicular line will have slope . You want to learn how Standard Form Equation for Line works.

Can you decide how to find the right-side constant term?
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

what is the equation of the line that passes through (–2, 4) and is perpendicular to 6x + 3y = 2
A.) 1/3x + 1/2y = 2
B.) x - 2y = -10
C.) 2x - y = 10
D.) 2x + 3y =6
Slope of line with equation, 6x + 3y = 2 is: - 2

Slope of line perpendicular to line with equation, 6x + 3y = 2 is: 

Using this slope, and the point, (- 2, 4) should give you the correct equation. 

Only one (1) equation has a slope, or m of  

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