SOLUTION: I do not understand how to find the standard equation of a line through the given point A (2,1) that satisfies the given condition(perpendicular to the y-axis)

Question 960511: I do not understand how to find the standard equation of a line through the given point A (2,1) that satisfies the given condition(perpendicular to the y-axis)
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Standard form as a generalized model can be .

If you solve for y in terms of x, you find slope is . "Perpendicular to the y axis", means slope is 0. Using the formula taken from standard form, this means . This means, .

You have so far, .

You want the line to contain the point A (2,1). The coordinate of x is no longer important; all possible values of x will be on the horizontal line (given now that slope is 0). y is 1 everywhere on this line.

, but also to give the slope-intercept form of the equation. Obviously this is only a constant, and therefore c/b is the y-intercept. You know that the line is .

If you really want as "STANDARD FORM", then adjustment is not needed. b=1, and c=1.
, but this is more formal than necessary.
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