SOLUTION: factor completely 125-27y^3

Question 95978: factor completely
125-27y^3
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
factor completely
125 - 27y^3
:
You should recognize this as "Difference of cubes" given in most textbooks as:
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
:
In our problem you can see 125 = 5^3 and 27 = 3^3, so we have:
:
(5 - 3y)(25 + (5*3y) + 9y^2
which is:
(5 - 3y)(25 + 15y + 9y^2)
:
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