SOLUTION: 2/3+3y=5y-2/15 i tried to put a 1 over the 3 and 5 with y's but i still couldn't figure it out. also i tried to subtract 2/3 from each side.

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Question 95589This question is from textbook Prentice Hall Algebra 1
: 2/3+3y=5y-2/15
i tried to put a 1 over the 3 and 5 with y's but i still couldn't figure it out. also i tried to subtract 2/3 from each side.
This question is from textbook Prentice Hall Algebra 1

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
2/3+3y=5y-2/15
Subtract 3y from both sides and gather the numbers on one side:
2y = (2/3)+(2/15)
2y = (10/15) + (2/15)
2y = 12/15
y = 6/15
y = 2/5
============
Cheers,
Stan H.

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