SOLUTION: A man left an estate of $64,000 to three children. the eldest child recieved three times as much as the youngest. the middle child received $14,000 more than the youngest. how m

Question 95582This question is from textbook
: A man left an estate of $64,000 to three children. the eldest child recieved three times as much as the youngest. the middle child received $14,000 more than the youngest. how much did each child recieve.
we know that
e=3y
m=y + 14000
m + y + e= 64000
and now i'm not sure how to set up the problem...please help This question is from textbook

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
E=3Y
M+Y+3Y=64000
M+4Y=64000
(Y+14000)+4Y=64000
Y+14000+4Y=64000
5Y=64000-14000
5Y=50000
Y=50000/5
Y=10000 AMOUNT GIVEN TO THE YOUNGEST.
E=3*10000=30000 FOR THE ELDEST
M+4*10000=64000
M+40000=64000
M=64000-40000
M=24000 AMOUNT GIVEN TO THE MIDDLE CHILD.
PROOF
10,000+30000+24000=64000
64000=64000
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