SOLUTION: x+y+z=1800 x=2(y+z) 20x+35y+50z=4800

Question 942536: x+y+z=1800
x=2(y+z)
20x+35y+50z=4800
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x+y+z=1800
x=2(y+z)
20x+35y+50z=4800
---
put the system of linear equations into standard form
---
x+y+z=1800
-x+2y+2z=0
20x+35y+50z=4800
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = 1200
y = 3280
z = -2680
---
Free algebra tutoring live chat:
https://sooeet.com/chat.php?gn=algebra
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations with quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
RELATED QUESTIONS
A theater owner want to divide an 1800 seat theatre in 3 sections. With tickets costing... (answered by Fombitz)

(y + z)/x - z/x (answered by Fombitz)

(x+y+z)^2=? (answered by jim_thompson5910)

x+y+z=-x^2-y^2+z... (answered by greenestamps,Alan3354)

(x+y-z)(x+y+z) (answered by richwmiller)

(x+y)-(y+z)-(z+x) (answered by sciwiz55)

Z=x+y ___... (answered by Fombitz)

(X+y)/z=(y-x) (answered by Alan3354)