SOLUTION: The perimeter of a rectangle is 46 ft. The width is 3ft less than twice the length. Find the length and width of the rectangle.

Question 941139: The perimeter of a rectangle is 46 ft. The width is 3ft less than twice the length. Find the length and width of the rectangle.
Answer by laoman(51) (Show Source): You can put this solution on YOUR website!
Let the length be l and width be w
From first statement, perimeter = 2(l+w)
2l+2w = 46
w = 2*l - 3
solving the simultaneous eqns
2l+2w = 46
2l-w = 3

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
We'll use substitution. After moving 2*w to the right, we get:
, or . Substitute that
into another equation:
and simplify: So, we know that w=14.3333333333333. Since , l=8.6666666666667.

Answer: .

length = 8.67 ft
width = 14.33 ft
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