------- eq (i)
------- eq (ii)
Let, and
Thenbecomes: 2a – 3b = - 5 ------ eq (iii)
Also,becomes: 4a + 6b = 14 ------- eq (iv)
4a – 6b = - 10 -------- Multiplying eq (iii) by 2 ----- eq (v)
8a = 4 ------- Adding eqs (v) & (iv)
a =, or
-------- Substituting ½ for a in eq (iii)
1 – 3b = - 5
– 3b = - 5 – 1
– 3b = - 6
b =, or 2
Since, then
------ Cross-multiplying
Since, then
2y = 1 ------ Cross-multiplying