SOLUTION: 5y^2+5y-25y-25=0
How do I solve this equation to find out what y is?
Algebra.Com
Question 936200: 5y^2+5y-25y-25=0
How do I solve this equation to find out what y is?
Found 2 solutions by MathLover1, rothauserc:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
...as you can see, all terms are divisible by ; so, we will simplify it first
...factor completely; first write as
...group
so, solutions are:
if then
if then
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
5y^2+5y-25y-25=0
5y^2-20y-25=0
divide both sides of = by 5
y^2-4y-5=0
factor polynomial
(y-5)(y+1)=0
y = 5 or -1
RELATED QUESTIONS
Solve each equation.... (answered by checkley71)
x=5y^2+25y+60 how do I graph... (answered by Alan3354)
Hello,
I've been trying to solve this problem but am stuck. Solve by Substitution... (answered by Alan3354)
The problem is this:
3x - 5y = -9
5x - 6y = -8
I believe that I did the first part (answered by solver91311)
4y^2-2y
_______
5y^2-5y
how do i solve this... (answered by stanbon)
use the addition-subtraction method to solve.
2x+5y=15
3x+5y=10
here,s what i came... (answered by josgarithmetic,MathTherapy)
Solve by graphing: x^2+y^2=25 and x-2y=-5
I graphed my circle and line perfectly
but... (answered by stanbon,bucky)
(5y-1)(y+1)/ 25y-5 Answer= y+5/5 Y cannot = 1/5
How do I break this down... (answered by jim_thompson5910)
Can you help me? I need to solve for y. The equation is 8/5y-2/3y=23-1/15y. I dont know... (answered by solver91311)