SOLUTION: Dear sir/madam, Thank you or taking the time to help me solve my problem. Here it is: Problem: If the complement of an angle is 5� less than one-sixth of its supplement, f

Question 935139: Dear sir/madam,
Thank you or taking the time to help me solve my problem. Here it is:
Problem:
If the complement of an angle is 5� less than one-sixth of its supplement, find the measure of the angle.
My attempt: (I'm having trouble writing the equation!!!)
Complimentary angles = 90 degrees, therefore:
90 - a
Supplementary angles = 180 degrees therefore:
180 - 1/6a - 5
Therefore:
90 -a = 180 -1/6a - 5
6(90) - 6(a) = 6(180) - 6(1/6)a - 6(5)
540 - 6a = 1080 - a - 30
540 - 6a = 1050 - a
540 - 540 - 6a = 1050 - 540 - a
- 6a = 510 - a

- 6a + a = 510
- 5a = 510
- 5a/5 = 510/5
-a = 102
a = - 102
Obviously an angle can't be negative so I must have written the wrong equation.
Any help you could provide would be most appreciated.
Kindest regards,
Mark Beaton
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
If the complement of an angle is 5� less than one-sixth of its supplement, find the measure of the angle.

;et angle be x
complimentary angle = (90-x)
supplementary angle = (180-x)
0n-sixth = (180-x)/6
5 less than = (180-x)/6 - 5
(90-x) =((180-x)/6) -5
90+5 = (180-x)/6 +x
95 = (180-x+6x)/6
570 = 180+5x
390 = 5x
x= 78 deg

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
x, the angle's measure.
90-x, the complement.
180-x, the supplement.

If the is PLUS , find the measure of the angle, x.

Form this equation:

Solve the equation for x.

RELATED QUESTIONS
Dear Sir/Madam; Please help me with a word problem, here it is: What is the... (answered by stanbon)
Dear Sir/Madam: A good day to you! Please help me in finding a solution to this... (answered by josgarithmetic)
Sir/Madam , Please help me to solve my problem . I Will be very grateful for your help. (answered by lwsshak3)
Dear Sir/madam; A pleasant day! please help me with this word problem about right... (answered by jsmallt9)
Dear Sir/Madam; A pleasant day! Please help me with this problem involving Division (answered by josh_jordan)
Dear Sir/Madam, Please help me solve this problem: Show that (1-sinA+cosA)^2 =... (answered by MathLover1)
Dear Sir/Madam, Good day! Kindly help me with this problem, I sent almost the same... (answered by reviewermath)
Dear Sir/Madam, A pleasant day! Please help me with this math problem, this is... (answered by lwsshak3)
Dear Sir/Madam, Please help me with this logarithm problem. If log2a + logbb... (answered by Theo)