SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

Question 93267: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Starting with the perimeter:
where s = the length of one of the equal sides and b = the length of the base and P = 29 cm.
But s = 4b-8 s is "8 cm less than 4 times the length of the base"
Substituting 4b-8 for s in the formula for the perimeter:
Simplify.

Add 16 to both sides.
Divide both sides by 9.
This is the length of the base, but you need the length of s, so...

cm.
Check:

RELATED QUESTIONS
The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by venugopalramana)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by Paul)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by checkley71)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by Nate)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by algebrapro18)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by checkley71)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by Nate)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by stanbon)

The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times... (answered by checkley75)