SOLUTION: Choose the one alternative that best completes the statement or answers the question. Solve by completing the square. x^2 - 6x - 40 = 0 a) 10, -4 b) -10, 4 c)(-36

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Question 93105: Choose the one alternative that best completes the statement or answers the question.
Solve by completing the square.
x^2 - 6x - 40 = 0
a) 10, -4 b) -10, 4 c)(-36, -4 d) square root of -40, negative square root of -40
I think the answer is d after I plugged in all the options, but I don't know how to prove it. When I try to use completing the square I get up to this point, 6 plus or minus the square root of 160 over 2 and I can't go any further. Thanks so much!!

Found 3 solutions by stanbon, tutorcecilia, jim_thompson5910:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solve by completing the square.
x^2 - 6x - 40 = 0
x^2-6x+? = 40+?
x^2+6x+[(1/2)6]^2 = 40 + [(1/2)6]^2
x^2+6x+9 = 40+9
(x+3)^2 = 49
x+3 = 7 or x+3 = -7
x = 4 or x = -10
================
Cheers,
Stan H.

Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!
x^2 - 6x - 40+40 =40
x^2-6x=40
}=

=
=
=49
=49 [factor]
= 49
=
x-3=+-7
x=3+-7
x=3+7=10
or
x=3-7=-4
.
Solution: (10 or -4)

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given equation


Add 40 to both sides


Take half of the x coefficient -6 to get -3 (ie )
Now square -3 to get 9 (ie )



Add this result (9) to both sides. Now the expression is a perfect square trinomial.




Factor into (note: if you need help with factoring, check out this solver)



Combine like terms on the right side

Take the square root of both sides

Add 3 to both sides to isolate x.

So the expression breaks down to
or


or Take the square root of 49 to get 7


or Now combine like terms

So our answer is
or


Here is visual proof

graph of

Here we can see that the x-intercepts are and , so this verifies our answer.

=========================================
Answer:
So the answer is A)

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