SOLUTION: x^3 - 4x^2 - 21x = 0
Algebra.Com
Question 92990: x^3 - 4x^2 - 21x = 0
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
factoring gives (x)(x-7)(x+3)=0 ... so x=0, x=7, x=-3
RELATED QUESTIONS
Solve for x:... (answered by mananth)
factor completely:
x^10y^3-4x^9y^2-21x^8y (answered by Earlsdon)
Factor completely
x^10y^3 – 4x^9y^2 – 21x^8y
(answered by jim_thompson5910)
f (x)= 4x^4 +21x^3 + 33x^2 + 147x +... (answered by MathLover1)
Given the zero: x=2, of the polynomial: x^3-4x^2+21x-34=0, find the others.
(answered by poliphob3.14,ewatrrr,htmentor)
solve for x:
7x^2 - 21x - 3 =... (answered by stanbon,TimothyLamb,josgarithmetic)
Solve for x.... (answered by )
Solve for X... (answered by )
Factor 4x^3+21x^2+29x+6 If (x+2) is one of its factors (answered by josgarithmetic)