SOLUTION: I am trying to solve this equation for c a (b-c) = a/b So far I have got to ab-ac=a/b ab=a/b+ac ab-a/b=ac But now I am stuck. Please help! Do I divide each side by a? How?

Algebra.Com
Question 928042: I am trying to solve this equation for c
a (b-c) = a/b
So far I have got to
ab-ac=a/b
ab=a/b+ac
ab-a/b=ac
But now I am stuck. Please help! Do I divide each side by a? How?

Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
So far I have got to
ab-ac=a/b
ab=a/b+ac
ab-a/b=ac
But now I am stuck. Please help! Do I divide each side by a? How?
-----------
ab-a/b=ac
b - 1/b = c

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

I am trying to solve this equation for c
a (b-c) = a/b
So far I have got to
ab-ac=a/b
ab=a/b+ac
ab-a/b=ac
But now I am stuck. Please help! Do I divide each side by a? How?

Yes, you need to divide both sides by "a" to isolate c






RELATED QUESTIONS

a(b-c)=ab-ac (answered by MathLover1)
a/bc + b/ac - c/ab =... (answered by hellyeah)
What is the basis for the distributive property? I know that the equation is a(b+c)=... (answered by ReadingBoosters,Ave,RedemptiveMath)
Complete the argument, giving a reason for each step. AB= BC Given AC= AB+BC... (answered by Edwin McCravy)
I have been working on this math problem and I think I got the answer, but I am not sure. (answered by solver91311)
Hello, in preparation for the quantitative portion of the GRE i came upon this question.... (answered by solver91311)
Given AC=BD ._____.________________._____. Prove AB=CD A B (answered by ikleyn)
If I have (1/A+1/B)^-1 That is AB/A+B What if it were (1/A+1/B+1/C)^-1 I am trying to (answered by robertb)
I am supposed to factor each expression. for a^2(b - c) - 16b^2(b - c) could you... (answered by stanbon)