SOLUTION: Find all real solutions, did I do this correctly? 4+√(x-2)=x √(x-2)=x-4 x-2=(x-4)^2 x-2=x^2 - 8x +16 x-2-x^2+8x-16=0 x^2+9x-18=0 -(x-3)(x-6)=0 so the answer i

Question 903740: Find all real solutions, did I do this correctly?
4+√(x-2)=x
√(x-2)=x-4
x-2=(x-4)^2
x-2=x^2 - 8x +16
x-2-x^2+8x-16=0
x^2+9x-18=0
-(x-3)(x-6)=0
so the answer is: +3,+6
Is there a easier way to solve these type of problems? Thanks
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
you did it right.
no there isn't an easier way.
you did it the way it's supposed to be done.

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SOLUTION: Find all real solutions, did I do this correctly? 4+&#8730;(x-2)=x &#8730;(x-2)=x-4 x-2=(x-4)^2 x-2=x^2 - 8x +16 x-2-x^2+8x-16=0 x^2+9x-18=0 -(x-3)(x-6)=0 so the answer i

SOLUTION: Find all real solutions, did I do this correctly? 4+√(x-2)=x √(x-2)=x-4 x-2=(x-4)^2 x-2=x^2 - 8x +16 x-2-x^2+8x-16=0 x^2+9x-18=0 -(x-3)(x-6)=0 so the answer i