SOLUTION: What is the equation of line that is perpendicular to 96x-24y-72=0 and passing through the midpoint between (-22,6) and (14,-16)? Kindly help !!

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Question 902096: What is the equation of line that is perpendicular to 96x-24y-72=0 and passing through the midpoint between (-22,6) and (14,-16)?
Kindly help !!

Found 2 solutions by josgarithmetic, Edwin McCravy:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Simplify your given equation!




can be solved for y.

Which is slope-intercept form for your given, now simplified, equation.

The line perpendicular to the given line will have slope , which is the negative
reciprocal of 4. That is how perpendicular lines in a plane work. The line you are looking
for is and you do not yet know what is b.

Next, you want to know the midpoint of the two given points, because you are told that
must include this point.
MIDPOINT: ;
This midpoint is (-4,-5).

You can solve the equation you want for b and use this found point (-4,-5) to get the value
of b.






Finish writing the equation asked for.


Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
What is the equation of line that is perpendicular to 96x-24y-72=0 and passing through the midpoint between (-22,6) and (14,-16)
First we find the slope of the line whose equation is

     

by solving it for y to get it in the form y=mx+b

           

Divide ever term through by -24

              
              
Compare that to y=mx+b and we see that m=4 and b=-3. We only need
the slope 4.  We don't need the y-intercept.

Any line perpendicular to a line whose slope is 4, has a slope which
is the reciprocal of 4 with the sign changed.  Therefore the slope
of the desired line will have slope .

Now we use the midpoint formula to find the midpoint between (-22,6) and
(14,-16)


Midpoint = 

where (x1,y1) = (-22,6)
and where (x2,y2) = (14,-16)

Midpoint = 

Midpoint = 

Midpoint = (-4,-5)

Next we use the point slope formula:


y - y1 = m(x - x1)
where m= and (x1,y1) = (-4,-5)

y - (-5) = 

y + 5 = (x + 4)

y + 5 = x - 1

    y = x + 6

Edwin


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