SOLUTION: Hello,
Would it be possible to get an answer for the equation:
Differentiate y=2sin2x.cos2x
Thank you in advance.
Algebra.Com
Question 892153: Hello,
Would it be possible to get an answer for the equation:
Differentiate y=2sin2x.cos2x
Thank you in advance.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
y=2sin2x.cos2x
y = 2sin(2x)cos(2x)
y' = 2*2*cos(2x)*cos(2x) + 2*2*sin(2x)*-sin(2x)
= 4cos^2(2x) - 4sin^2(2x)
= 4cos(4x)
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