SOLUTION: For the quadratic function Q(x)=x^2+5x-36, determine the exact location of the minimum.
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Question 89208: For the quadratic function Q(x)=x^2+5x-36, determine the exact location of the minimum.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Q(x) = x^2 + 5x - 36
Since the vertex is the tip of the function, it is the lowest, minimal, value.
(-2.5,-42.25)
-42.25 is the minimum
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