SOLUTION: Divide 56 into two parts such that 3/8 of the greater exceeds 1/4 of the smaller by 6.

Question 891589: Divide 56 into two parts such that 3/8 of the greater exceeds 1/4 of the smaller by 6.

Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
let x = the smaller part
This means 56-x is the smaller
(3/8)(56-x) - (1/4)(x) = 6
multiply each side by 8 to get rid of the fractions
3(56-x) - 2(x) = 48
168 - 3x - 2x = 48
168 - 5x = 48
add -168 to each side
-5x = 48 -168
-5x = -120
divide each side by -5
x = 24
(56 -x ) = 56 - 24 = 32
So the larger is 32 and the smaller is 24
Plugging into our equation,
(3/8)(56-24) -(1/4)(24) ?= 6
(3/8)(32) - 6 ?= 6
12 - 6 ?= 6 , clearly yes

RELATED QUESTIONS
Divide rs.350 into two parts such that the half of greater part exceeds the smaller part... (answered by Cromlix)

i need help with this problem divide 56 into two parts such that 3/8 of the larger... (answered by swincher4391)

Divide 56 into two parts such that 3/8 of the larger number decreased by 6 equals 1/4 if... (answered by stanbon)

Divide 56 Into Two Parts Such That Three Times The First Parts Exceeds One Third Of The... (answered by lynnlo)

Divide 56 into two parts such that three times the first part exceeds one third of the... (answered by Boreal)

Divide 56 into two parts such that three times the first part exceeds one third of the... (answered by josgarithmetic)

Divide 56 into two parts such that three times the first part exceeds one third of the... (answered by math_helper)

Please help me how to solve this.....Divide 60 into 2 parts such that twice the smaller... (answered by solver91311)

divide 30 into 2 equal parts such that the square of the smaller part exceeds the other... (answered by checkley77)