SOLUTION: I need help figuring this out. Thank you.
Solve 2 sin^2 a-5 sin a-3=0 in the interval 0° <= m(a)< 360°
Algebra.Com
Question 888891: I need help figuring this out. Thank you.
Solve 2 sin^2 a-5 sin a-3=0 in the interval 0° <= m(a)< 360°
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let
Two solutions:
Not a valid solution.
.
.
.
degrees and degrees
RELATED QUESTIONS
I need help figuring out all the solutions in the interval [0,2pi)... (answered by ikleyn)
Find all solutions of the equation 3 sin^2 x - 7 sin x + 2 = 0 in the interval [0,2pi).
(answered by Fombitz)
please help me solve this equation: solve exactly: sin(x) + 4csc(x) + 5=0
I have... (answered by stanbon)
Please help me with this problem. I need to solve the equation for solutions over the... (answered by Gogonati)
I need help figuring out the exact value for this expression.
sen(a)=... (answered by stanbon)
Please help me Solve this equation on [0,360)
sin^3 (x) = sin(x)
Thank you in... (answered by Theo,greenestamps)
Solve sin^2 x - sin x - 2 = 0 for 0 < x < 360
Thanks a... (answered by jsmallt9)
Solve the equation in the interval (0 degrees, 360 degrees)
sin^2 theta-sin... (answered by ikleyn,greenestamps)
I'm having a hard time figuring this out.
Thank you in advance.
I need to solve this:
(answered by josmiceli)