SOLUTION: equations in quadratic form;
solve the equation for x;
x^6-28x^3+27=0
Algebra.Com
Question 886359: equations in quadratic form;
solve the equation for x;
x^6-28x^3+27=0
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
x^6-28x^3+27=0
factor polynomial
(x^3 -27)(x^3-1) = 0
we have two cases
x^3 -27 = 0
x = 3
and
x^3 -1 = 0
x = 1
our two solutions are x = 3 or 1
RELATED QUESTIONS
x^6-28x^3+27=0 (answered by ankor@dixie-net.com)
SOLVE CUBIC EQUATION X^3 + 3X^2 - 28X =... (answered by venugopalramana)
place the following equations in the standard form of a quadratic equation (ax^2+bx+c=0)
(answered by ichudov)
Solve the quadratic equation... (answered by jim_thompson5910)
solve... (answered by xcentaur)
Solve for x the following quadratic equations by factoring
X squared - 5x... (answered by TimothyLamb)
Use the quadratic formula to solve equation. Write irrational roots in the simplest... (answered by solver91311)
Solve for x the following quadratic equations by factoring
X squared... (answered by TimothyLamb,MathLover1)
Write the equation in quadratic form and solve by factoring.
x(x-7) + 12 =... (answered by MathLover1)