SOLUTION: Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).

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Question 880812: Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).

Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Write an equation for the line perpendicular to y = 5x – 12
that contains (–3, –1).
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The given equation has slope = 5
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The desired equation must have slope = -1/5
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Form: y = mx + b
Solve for "b" when m = -1/5 and y = -1 when x = -3
==================
-1 = (-1/5)(-3) + b
-1 = (3/5) + b
b = -8/5
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Equation:
y = (-1/5)x - (8/5)
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Cheers,
Stan H.

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.


Use the point slope form,
}


.
.
.


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