SOLUTION: Hey, I'm on a question where you have to solve the question that a student has attempted but is wrong, I can't seem to find the problem. Are you able to help me please? Here

Question 875488: Hey,
I'm on a question where you have to solve the question that a student has attempted but is wrong, I can't seem to find the problem. Are you able to help me please?
Here is a picture of the students workout and question.
http://gyazo.com/df24ccae44177730e6f7a41db326a995
Be much help, thank you.
Found 2 solutions by rothauserc, Theo:
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
This is a complete the square problem
2x^2 +4x - 4 = 0
divide by 2
x^2 + 2x - 2 = 0
now add -2 to both sides of =
x^2 +2x = 2
take 1/2 of 2 and square it, then add to both sides of =
x^2 +2x + 1 = 3
(x +1)^2 = 3
take square root of both sides of =
x+1 = square root(3)
x = square root(3) - 1
x = +square root(3) - 1
x = -square root(3) -1
To the student, remember when completing the square to move the loose number (-2) to the right of the equal sign and square root means + or - square root

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
here's the link that you showed me.
http://gyazo.com/df24ccae44177730e6f7a41db326a995
here's the corrected solution:

the standard form of the quadratic equation is ax^2 + bx + c
if you divide by a you get:
x^2 + (b/a)x + c/a = 0
you have to take 1/2 of the coefficient of the x term.
you will then get:
(x + b/2a)^2 - (b/2a)^2 + c = 0
the student didn't take half of the coefficient of the x term.
that was the student's first mistake.
then when the student took the square root of both sides of the equation, the student only took the positive side of the square root and not the negative side of the square root.
that was the second mistake.

RELATED QUESTIONS
Hey, I can't seem to figure the answer to this question, I've tried but doesn't seem... (answered by Alan3354)
I'm stuck on a question involving the method of substitution. The question wants me to... (answered by stanbon)
good evening, I am not sure if this is where I need to ask the question on solving... (answered by ankor@dixie-net.com)
Hello! I have a quick question on polynomials. I am being asked to determine if 8/3 x^9/3 (answered by mananth)
I have been trying to solve this question but I'm not following. A student earned a... (answered by rothauserc,MathTherapy,fractalier)
Hi I have two homework problems that I cannot seem to quite get. In class and with my... (answered by jim_thompson5910)
I am having a problem with getting to the final answer. I seem to have the set up... (answered by jim_thompson5910)
hey i will really really appreciate it if you could help me with this probability... (answered by edjones)
hey, I need help on rationalizing a denominator. the question is 5/root 10. I know... (answered by josmiceli,MathTherapy)