SOLUTION: Find 'n'
1+3+...+2n-1=10(4n+50)
Do I have to do something with (2n-1+2)(2n-1)
I have no idea. Please help.
Algebra.Com
Question 863270: Find 'n'
1+3+...+2n-1=10(4n+50)
Do I have to do something with (2n-1+2)(2n-1)
I have no idea. Please help.
Found 2 solutions by metodi022, lenny460:
Answer by metodi022(3) (Show Source): You can put this solution on YOUR website!
Answer by lenny460(1073) (Show Source): You can put this solution on YOUR website!
Please repost your question.
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