SOLUTION: Hi, how can I get this:
[((x-3)^2)/4]-[((y+2)^2)/16]=1
from this: 4x^2-y^2-24x-4y+16=0
Thanks!
Algebra.Com
Question 861881: Hi, how can I get this:
[((x-3)^2)/4]-[((y+2)^2)/16]=1
from this: 4x^2-y^2-24x-4y+16=0
Thanks!
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
4x^2-y^2-24x-4y+16=0
Completing the Square
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