SOLUTION: Tutor could you help me please? How do I: Subtract 2x/x^2-13x+42 minus 7/x-6

Question 86149: Tutor could you help me please? How do I: Subtract
2x/x^2-13x+42 minus 7/x-6
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[2x/x^2-13x+42] - [7/x-6]
Factor to get:
[2x/ (x-7)(x-6)] - [7/(x-6)]
----------------
The lcm is (x-7)(x-6)
-------------
Write each fraction with the lcm as its denominator:
= [2x/lcm] - [7(x-7)/lcm]
-------------
Combine the numerators to get:
= [2x-7x+49]/lcm
= [-5x+49]/[(x-6)(x-7)]
=============
Cheers,
Stan H.

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