SOLUTION: 3(r + 3) + 2(r - 4)

Algebra.Com
Question 860347: 3(r + 3) + 2(r - 4)
Answer by lenny460(1073)   (Show Source): You can put this solution on YOUR website!
3(r + 3) + 2(r - 4)

3 * r = 3r
3 * 3 = 9
2 * r = 2r
2 * -4 = -8
Therefore:
3r + 9 + 2r - 8
3r + 2r = 5r
9 - 8 = 1

Answer:
5r + 1


Lennox Obuong
Algebra Tutor

RELATED QUESTIONS

7-3=r-4(2+r) (answered by funmath)
Please describe and correct the error: (r^2-7r+12/r+4)/(r^2-7r+12/r^2+6r+8)=... (answered by jsmallt9)
Please describe and correct the error.
  {{{((r^2 -7r +12)/(r+4))  /  ((r^2... (answered by Edwin McCravy)
I really need some help describing and correcting the error. r^2-7r+12/ r+4 divided by (answered by stanbon,TeachMath)
8(4-r)+r=-6(3+r) (answered by ReadingBoosters)
Please help me solve for R for this equation: {{{(3/(5+R)) + (R/(R+2))=(R+4)/(R+5)... (answered by rmromero)
r(t)=t^2-5t+4 over t^2-9 r(1) r(2)... (answered by rapaljer)
Let r_1, r_2, r_3, r_4, and r_5 be the complex roots of x^5 - 4x^2 + 7x - 1 = 0. Compute (answered by CPhill,ikleyn)