SOLUTION: x2+5y−4=0 y−x=−2 How do i change x^2+5y-4=0 into a circle equation and y-x=-2 into a line equation? This is for systems of equations with circles, solving b

Question 858375: x2+5y−4=0
y−x=−2
How do i change x^2+5y-4=0 into a circle equation and y-x=-2 into a line equation?
This is for systems of equations with circles, solving by graphing. Thanks for your time!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
There's no circle.
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y-x = 2 is the equation of a line. To be more exact, the graph of y-x = 2 is a straight line.
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PS Use ^ (Shift 6) for exponents.
eg, x^2, not x2

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SOLUTION: x2+5y&#8722;4=0 y&#8722;x=&#8722;2 How do i change x^2+5y-4=0 into a circle equation and y-x=-2 into a line equation? This is for systems of equations with circles, solving b

SOLUTION: x2+5y−4=0 y−x=−2 How do i change x^2+5y-4=0 into a circle equation and y-x=-2 into a line equation? This is for systems of equations with circles, solving b