SOLUTION: Hi, I need help on getting this answer Solve for x and y by elimination or substitution <img src="http://formula.algebra.com/cgi-bin/plot-formula.mpl?expression=%0D%0A%28x-2%29%2

Question 856404: Hi, I need help on getting this answer
Solve for x and y by elimination or substitution

Found 2 solutions by mananth, KMST:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Solve for x and y by elimination or substitution

multiply equation by 15
5(x-2)+3(y+1) = 30
5x-10+3y+3=30
5x+3y=37................................(1)

multiply equation by 21 (7*3)
3(x+2)-7(y+5)=-42
3x+6-7y-35=-42
3x-7y=-13..................................(2)
5 x + 3 y = 37 .............1
Total value
3 x -7 y = -13 .............2
Eliminate y
multiply (1)by 7
Multiply (2) by 3
35 x 21 y = 259
9 x -21 y = -39
Add the two equations
44 x = 220
/ 44
x = 5
plug value of x in (1)
5 x + 3 y = 37
25 + 3 y = 37
3 y = 37 -25
3 y = 12
y = 4
(5,4)

Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
There is more than one way to go about it, but I do not like to have to write all those denominators.
To start, I would eliminate denominators by multiplying times a convenient factor, and the I would simplify:

-->-->-->-->-->

-->-->-->-->-->

Then I would set to solve the system
by elimination.
Multiplying the first equation times 3, and the second times -5,
and adding the resulting equations, I would get
15x + 9y = 111
-15x +35y = 65
-----------------
0x +44y = 176 --> --> -->
Then I would substitute 4 for y in to get
-->-->-->-->-->
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