SOLUTION: An investor has $5000 to invest and decides to invest some of it with company A and the rest with company B. After one year each $1 invested with company A has grown to $1.20, each

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Question 856061: An investor has $5000 to invest and decides to invest some of it with company A and the rest with company B. After one year each $1 invested with company A has grown to $1.20, each dollar invested with company B has grown to $1.05 and the $5000 has grown to $5670. How much of the original $5000 was invested with each company?
Answer by ramkikk66(644)   (Show Source): You can put this solution on YOUR website!
Say he invested $x in A. So amount invested in B is 5000 - x.
Total earned from A = 1.2 * x  ---> every $ becomes $1.2
Total earned from B = 1.05 * (5000 - x) ----> every $ becomes $1.05

Total = 
i.e. 
Simplifying:
 or 
So, amount invested in A is $2800, and that invested in B is $2200.
Check: 2800 becomes 2800  * 1.2 = 3360
2200 becomes 2200 * 1.05 = 2310
Total = 3360 + 2310 = 5670. Correct!


Hope this is clear :)


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