Hi,

(1/a+3)-(a/a^2-9)=(2/3-a)

1/(a+3)- a/(a+3)(a-3)= -2/(a-3)  |Note Parenthesis used to show terms in denominator 

|Multiplying thru by (a+3)(a-3) so as all denominators = 1

 (a-3) - a + 2(a+3) = 0

      2a +3 = 0

       2a = -3

        a = -3/2 

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