SOLUTION: Solve. –6(x + 3) – 10 = 3(–2x – 5) – 13 Here is what I ahve -6(3 + x) + -10 = 3(-2x + -5) + -13 (3 * -6 + x * -6) + -10 = 3(-2x + -5) + -13 (-18 + -6x) + -10 = 3(-2x + -5)

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Question 85332: Solve. –6(x + 3) – 10 = 3(–2x – 5) – 13
Here is what I ahve
-6(3 + x) + -10 = 3(-2x + -5) + -13
(3 * -6 + x * -6) + -10 = 3(-2x + -5) + -13
(-18 + -6x) + -10 = 3(-2x + -5) + -13
-18 + -10 + -6x = 3(-2x + -5) + -13
-18 + -10 = -28
-28 + -6x = 3(-2x + -5) + -13
-28 + -6x = 3(-5 + -2x) + -13
-28 + -6x = (-5 * 3 + -2x * 3) + -13
-28 + -6x = (-15 + -6x) + -13
-28 + -6x = -15 + -13 + -6x
-15 + -13 = -28
-28 + -6x = -28 + -6x
-28 + 28 + -6x = -28 + 28 + -6x
-28 + 28 = 0
0 + -6x = -28 + 28 + -6x
-6x = -28 + 28 + -6x
-28 + 28 = 0
-6x = 0 + -6x
-6x = -6x
-6x + 6x = -6x + 6x
-6x + 6x = 0
0 = -6x + 6x
-6x + 6x = 0

Answer by mszlmb(115)   (Show Source): You can put this solution on YOUR website!
Distribute
add 28 to both sides
Divide by negative one


This means that for this particular equation, x can be ANY value.
The domain is (-infinity, infinity)
Any X value will satisfy the equation above ^_^

For example, x can equal (any number, even) one:
-6(1+3)-10=3(-2(1)-5)-13
-6(4)-10=3(-7)-13
-24-10=-21-13
-34=-34  Thus the equation is satisfied.

Another example:  X=0 (note please that all values of x will satisfy this equation)
-6(0+3)-10=3(-2(0)-5)-13
-6(3)-10=3(-5)-13
-28=-28

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