SOLUTION: Solve. 10(�x � 7) + 20 = �5(2x + 4) Here is what I ahve 10(-7 + -1x) + 20 = -5(2x + 4) (-7 * 10 + -1x * 10) + 20 = -5(2x + 4) (-70 + -10x) + 20 = -5(2x + 4) -70 + 20 + -10

Question 85331: Solve. 10(�x � 7) + 20 = �5(2x + 4)
Here is what I ahve
10(-7 + -1x) + 20 = -5(2x + 4)
(-7 * 10 + -1x * 10) + 20 = -5(2x + 4)
(-70 + -10x) + 20 = -5(2x + 4)
-70 + 20 + -10x = -5(2x + 4)
-70 + 20 = -50
-50 + -10x = -5(2x + 4)
-50 + -10x = -5(4 + 2x)
-50 + -10x = (4 * -5 + 2x * -5)
-50 + -10x = (-20 + -10x)
-50 + -10x + 10x = -20 + -10x + 10x
-10x + 10x = 0
-50 + 0 = -20 + -10x + 10x
-50 = -20 + -10x + 10x
-10x + 10x = 0
-50 = -20 + 0
-50 = -20

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation

Distribute

Multiply

Add 10x to both sides

Notice the x terms add to zero

Combine like terms

Since this equation is false no matter what x is equal to (x is not a factor in this equation any more), there are no solutions. Notice if we graph the equations
here is the left equation in y form
here is the right equation in y form

we get

and here you can clearly see that these two parallel lines will never intersect. Since they never intersect, there are no solutions.
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