SOLUTION: dy/dx=1/y(y^4/x^2-y^2/2x) given v= y^2/2x

SOLUTION: dy/dx=1/y(y^4/x^2-y^2/2x) given v= y^2/2x

Algebra.Com

Question 844492: dy/dx=1/y(y^4/x^2-y^2/2x) given v= y^2/2x
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
What's the question?
Please repost.

RELATED QUESTIONS
sopve the differential equation : (x^2-y^2)*dy=2xy*dx 1. dy*6x+dy(-y^2)=2x^2yd 2. (answered by kekegeter ,robertb)

Dy/dx=(x+y+1)^2 (answered by MathLover1)

if y=f((2x-1)/(x^2+1)) , f'(x)=sin(x^2) find... (answered by KMST)

Find dy/dx given that... (answered by jsmallt9)

y=x^2(3x+1) find... (answered by Timnewman)

solve the differential equation: y dy/dx = x(y^4 + 2(y)^2 + 1) at x= -3 ,... (answered by solver91311,ikleyn)

Given that dy/dx=a/x^2+1 and that when x=1 dy/dx=3 and y=3 find the value of y when... (answered by solver91311)

Given that dy/dx=a/x^2 +1 and that when x=1 dy/dx=3 and y=3 find the value of y when... (answered by solver91311)

Given that y=x-√1+x^2 Show that... (answered by robertb)