SOLUTION: let g and h be two functions defined by: g(x)=(x-1)(x-6) h(x)=-9x+1 for any real number x. Find g/h(2) and then find all values that are NOT in the domain of g/h.

Algebra.Com
Question 842649: let g and h be two functions defined by:
g(x)=(x-1)(x-6)
h(x)=-9x+1
for any real number x.
Find g/h(2) and then find all values that are NOT in the domain of g/h. If there is more than one value, separate them with commas.
so I have g/h(2):
(x-1)(x-6)/-9x+1(2)
I don't know how to find the values that are NOT in the domain of g/h.

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
h(2)=-9*2+1
h(2)=-17

.
The domain for this is all real numbers.

The domain for ?
.
Values of x NOT in the domain of g/h is only one value.
The ratio g/h cannot accept


-------This is the value of x NOT in the domain of .

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